Abstract
Paths P1, … , Pk in a graph G= (V, E) are mutually induced if any two distinct Pi and Pj have neither common vertices nor adjacent vertices. The Induced Disjoint Paths problem is to decide if a graph G with k pairs of specified vertices (si, ti) contains k mutually induced paths Pi such that each Pi starts from si and ends at ti. This is a classical graph problem that is NP-complete even for k= 2. We introduce a natural generalization, Induced Disjoint Connected Subgraphs: instead of connecting pairs of terminals, we must connect sets of terminals. We give almost-complete dichotomies of the computational complexity of both problems for H-free graphs, that is, graphs that do not contain some fixed graph H as an induced subgraph. Finally, we give a complete classification of the complexity of the second problem if the number k of terminal sets is fixed, that is, not part of the input.
| Original language | English |
|---|---|
| Pages (from-to) | 2580-2604 |
| Number of pages | 25 |
| Journal | Algorithmica |
| Volume | 85 |
| Issue number | 9 |
| DOIs | |
| Publication status | Published - 11 Mar 2023 |
Bibliographical note
Funding Information:The authors thank Paweł Rzążewski for the argument using blob graphs, which simplified two of our proofs and led to the case H = P 6 \documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document}$$H=P_6$$\end{document} in Theorem 1. The paper did not receive support from external funding agencies.
Publisher Copyright:
© 2023, The Author(s).
Keywords
- Complexity dichotomy
- Connectivity
- H-free graph
- Induced subgraphs
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