On the circle, $GMC^{\gamma} = C\beta E_{\infty}$ for $\gamma = \sqrt{\frac{2}{\beta}}$, ($\gamma \leq 1$)

Reda Chhaibi, Joseph Najnudel

Research output: Contribution to journalArticle (Academic Journal)peer-review

Original languageEnglish
JournalarXiv
Publication statusSubmitted - 2019

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