Original language | English |
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Journal | arXiv |
Publication status | Submitted - 2019 |
On the circle, $GMC^{\gamma} = C\beta E_{\infty}$ for $\gamma = \sqrt{\frac{2}{\beta}}$, ($\gamma \leq 1$)
Reda Chhaibi, Joseph Najnudel
Research output: Contribution to journal › Article (Academic Journal) › peer-review